本文共 1181 字，大约阅读时间需要 3 分钟。

题目：

Given a list of daily temperatures T, return a list such that, for each day in the input, tells you how many days you would have to wait until a warmer temperature. If there is no future day for which this is possible, put 0 instead.

For example, given the list of temperatures T = [73, 74, 75, 71, 69, 72, 76, 73], your output should be [1, 1, 4, 2, 1, 1, 0, 0].

Note: The length of temperatures will be in the range [1, 30000]. Each temperature will be an integer in the range [30, 100].

解释：

class Solution:    def dailyTemperatures(self, T):        """        :type T: List[int]        :rtype: List[int]        """        ans=[0]*len(T)        stack=[]        for i in range(len(T)):            while stack and T[stack[-1]]

c++代码：

#include 
   
    using namespace std;class Solution {
   public:    vector
    
      dailyTemperatures(vector
     
      & T) {
           stack
      
       _stack;        int n=T.size();        vector
       
        result(n,0);        for(int i=0;i
       
      
     
    
   

总结：

转载地址：http://oglcn.baihongyu.com/